모두CBT
F(s)=1(2s+1)(s+2)F(s)=\dfrac{1}{(2s+1)(s+2)}F(s)=(2s+1)(s+2)1의 역 라플라스 변환은?
f(t)=13e−12t−13e−2tf(t)=\dfrac{1}{3}e^{-\frac{1}{2}t}-\dfrac{1}{3}e^{-2t}f(t)=31e−21t−31e−2t
f(t)=23e−12t−23e−2tf(t)=\dfrac{2}{3}e^{-\frac{1}{2}t}-\dfrac{2}{3}e^{-2t}f(t)=32e−21t−32e−2t
f(t)=13e−12t+13e−2tf(t)=\dfrac{1}{3}e^{-\frac{1}{2}t}+\dfrac{1}{3}e^{-2t}f(t)=31e−21t+31e−2t
f(t)=23e−12t+23e−2tf(t)=\dfrac{2}{3}e^{-\frac{1}{2}t}+\dfrac{2}{3}e^{-2t}f(t)=32e−21t+32e−2t
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