액체연료 1kg을 완전연소 하는데 필요한 이론공기량 Ao(Sm3/kg) 상세 페이지

$\mathrm{A_o} = 0.21\left(\dfrac{22.4}{12}\mathrm{C} + \dfrac{11.2}{2}\left(\mathrm{H} - \dfrac{\mathrm{O}}{8}\right) + \dfrac{22.4}{32}\mathrm{S}\right)$

$\mathrm{A_o} = \dfrac{1}{0.21}\left(\dfrac{22.4}{12}\mathrm{C} + \dfrac{22.4}{2}\left(\mathrm{H} - \dfrac{\mathrm{O}}{8}\right) + \dfrac{22.4}{32}\mathrm{S}\right)$

$\mathrm{A}_\mathrm{o} = 0.21\left(\dfrac{22.4}{12}\mathrm{C} + \dfrac{11.2}{2}\left(\mathrm{H} - \dfrac{\mathrm{O}}{8}\right) + \dfrac{22.4}{32}\mathrm{S}\right)$