모두CBT
그림과 같은 브리지 회로의 평형 조건은? (단, 전원 주파수는 일정하다.)
R1R3+R2R4=LC, R4R2=LCR_1R_3 + R_2R_4 = \dfrac{L}{C},\ \dfrac{R_4}{R_2} = \dfrac{L}{C}R1R3+R2R4=CL, R2R4=CL
R1R3+R2R4=LC, R4R2=1ω2LCR_1R_3 + R_2R_4 = \dfrac{L}{C},\ \dfrac{R_4}{R_2} = \dfrac{1}{\omega^2 LC}R1R3+R2R4=CL, R2R4=ω2LC1
R1R3−R2R4=LC, R4R2=LCR_1R_3 - R_2R_4 = \dfrac{L}{C},\ \dfrac{R_4}{R_2} = \dfrac{L}{C}R1R3−R2R4=CL, R2R4=CL
R1R3−R2R4=LC, R4R2=1ω2LCR_1R_3 - R_2R_4 = \dfrac{L}{C},\ \dfrac{R_4}{R_2} = \dfrac{1}{\omega^2 LC}R1R3−R2R4=CL, R2R4=ω2LC1
