모두CBT
3상 불평형 전압을 Va, Vb, Vc 라고 할 때 역상전압 V2는?
V2=13(Va+Vb+Vc)V_2=\dfrac{1}{3}(V_a+V_b+V_c)V2=31(Va+Vb+Vc)
V2=13(Va+aVb+a2Vc)V_2=\dfrac{1}{3}(V_a+aV_b+a^2V_c)V2=31(Va+aVb+a2Vc)
V2=13(Va+a2Vb+Vc)V_2=\dfrac{1}{3}(V_a+a^2V_b+V_c)V2=31(Va+a2Vb+Vc)
V2=13(Va+a2Vb+aVc)V_2=\dfrac{1}{3}(V_a+a^2V_b+aV_c)V2=31(Va+a2Vb+aVc)