모두CBT
G(s)H(s)=K(s+1)s2(s+2)(s+3)G(s)H(s)=\dfrac{K(s+1)}{s^2(s+2)(s+3)}G(s)H(s)=s2(s+2)(s+3)K(s+1)에서 점근선의 교차점을 구하면?
−56-\dfrac{5}{6}−65
−15-\dfrac{1}{5}−51
−43-\dfrac{4}{3}−34
−13-\dfrac{1}{3}−31