모두CBT
G(jw)=1jwT+1G(jw)=\dfrac{1}{jwT+1}G(jw)=jwT+11의 크기와 위상각은?
G(jw)=w2T2+1∠tan−1wTG(jw)=\sqrt{w^2T^2+1}\angle\tan^{-1}wTG(jw)=w2T2+1∠tan−1wT
G(jw)=w2T2+1∠−tan−1wTG(jw)=\sqrt{w^2T^2+1}\angle-\tan^{-1}wTG(jw)=w2T2+1∠−tan−1wT
G(jw)=1w2T2+1∠tan−1wTG(jw)=\dfrac{1}{\sqrt{w^2T^2+1}}\angle\tan^{-1}wTG(jw)=w2T2+11∠tan−1wT
G(jw)=1w2T2+1∠−tan−1wTG(jw)=\dfrac{1}{\sqrt{w^2T^2+1}}\angle-\tan^{-1}wTG(jw)=w2T2+11∠−tan−1wT