모두CBT
R(z)=(1−e−aT)z(z−1)(z−e−aT)R(z)=\dfrac{(1-e^{-aT})z}{(z-1)(z-e^{-aT})}R(z)=(z−1)(z−e−aT)(1−e−aT)z 의 역변환은?
teaT
te-aT
1-e-aT
1+e-aT