모두CBT
블록선도의 전달함수가 C(s)/R(s)=10과 같이 되기 위한 조건은?
G(s)=11−H1(s)−H2(s)G(s)=\dfrac{1}{1-H_1(s)-H_2(s)}G(s)=1−H1(s)−H2(s)1
G(s)=101−H1(s)−H2(s)G(s)=\dfrac{10}{1-H_1(s)-H_2(s)}G(s)=1−H1(s)−H2(s)10
G(s)=11−10H1(s)−10H2(s)G(s)=\dfrac{1}{1-10H_1(s)-10H_2(s)}G(s)=1−10H1(s)−10H2(s)1
G(s)=101−10H1(s)−10H2(s)G(s)=\dfrac{10}{1-10H_1(s)-10H_2(s)}G(s)=1−10H1(s)−10H2(s)10
