☆탄소가 85%인 중유를 연소시키니 습연소가스 중의 SO2 함… | 직8딴_대기환경기사_계산형(1~50) 상세 페이지

해설

$SO_2(\%)=\frac{SO_2\text{발생량}}{G_w}\cdot 100$

→ $0.0025=\frac{0.007a}{15.864-0.359a}$ → $0.04-0.001a=0.007a$ → $a=5\%$

$G_w=(m-0.21)A_o+CO_2+SO_2+H_2O=(1.3-0.21)\cdot(11.557-0.233a)+1.587+0.007a+1.68-0.112a=15.864-0.359a\,\mathrm{Sm^3/kg}$

$C+O_2\rightarrow CO_2$

12kg : 22.4Sm³ : 22.4Sm³

0.85 : X : X

→ $X=\frac{22.4\cdot 0.85}{12}=1.587\,\mathrm{Sm^3/kg}$

$H_2+0.5O_2\rightarrow H_2O$

2kg : 0.5·22.4Sm³ : 22.4Sm³

0.01(15-a) : X : Y

→ $X=\frac{0.5\cdot 22.4\cdot 0.01(15-a)}{2}=0.84-0.056a\,\mathrm{Sm^3/kg}$

$Y=\frac{22.4\cdot 0.01(15-a)}{2}=1.68-0.112a\,\mathrm{Sm^3/kg}$

$S+O_2\rightarrow SO_2$

32kg : 22.4Sm³ : 22.4Sm³

0.01a : X : X

→ $X=\frac{22.4\cdot 0.01a}{32}=0.007a\,\mathrm{Sm^3/kg}$

$A_o=\frac{O_o}{0.21}=\frac{1.587+0.84-0.056a+0.007a}{0.21}=11.557-0.233a$

m = 1.3

CO₂ = 1.587Sm³/kg

SO₂ = 0.007a Sm³/kg

H₂O = 1.68 - 0.112a Sm³/kg

SO₂발생량 = 0.007a Sm³/kg

정답

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